When stating about projectile motion, in simple words, it is stated as a two dimensional motion. Any particle body when thrown near the surface of theearth, it moves in a certain motion along its curved path, that too under the action of earth’s gravity. That motion is called projectile motion.

After analyzing from a graph, you will find that there isn’t any presence of x component of gravity.

From that analysis, you can see,

ax= 0, and

a_{y} = -g

Let initial velocity be, (v_{x} )_{0}

When initial velocity remains the same throughout the projectile motion, another equation comes to the forefront.

V _{x} = (vx)_{0}

v_{y} = (v_{y}) 0 –gt

x = x_{0} +(vx)_{0} t

y = y0 +(vy)_{0} t -gt^{2}

v^{2}_{y} = (v _{y})2_{0} – 2g (y – y_{0})

After calculation, if you do not find x_{0 }and y_{0}in the initial phase, which you can find as x_{0 }= 0 and y_{0 }= 0, then you need to start the same calculation from the beginning.

**Links of Previous Main Topic:-**

- Introduction about distributed forces
- Area moments of inertia in rectangular and polar coordinates
- Mass moment of inertia introduction
- Work done by force
- Kinematics of particles
- Position vector velocity and acceleration
- Rectangular components of velocity and acceleration

**Links of Next Mechanical Engineering Topics:-**