Fig. 6.5 describes an area of constant thickness which is denoted by t. Therefore the mass of elemental i.e. dm is given by
dm = ptdA p, t are constants, dA =elemental area.
From equation (6.2), we have
x = ʃ x dA / A , y = ʃ y dA / A , z = ʃ z dA / A
In equation (6.6), ʃ x dA, ʃ y dA, ʃ z dA are referred as first moment of area.
Links of Previous Main Topic:-
- Introduction to statics
- Introduction to vector algebra
- Introduction concept of equilibrium of rigid body
- Friction introduction
- Introduction about distributed forces
- Center of gravity and center of mass
Links of Next Mechanical Engineering Topics:-
- Centroids of volumes
- Centroidal coordinate of elemental area
- Centroidal coordinate of elemental volume
- Coordinates of centre of mass of composite bodies and figures
- Area moments of inertia in rectangular and polar coordinates
- Mass moment of inertia introduction
- Work done by force
- Kinematics of particles
- Position vector velocity and acceleration
- Plane kinematics of rigid bodies introduction