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We have already Pv n=C
V n d P + P n v n 1 dv = 0
dp / du = – n p / u
slope = – n p / u
From there we get that slope depends on P and v for a particular n, in negative sense.
| Process | Value of n | Equation of process |
| Isobaric Process
Isothermal Process Isentropic Process Isometric or isochoric Process |
n = 0
n = 1 n = y · |
P = Const.
T = Const. S = Const. v = Const. |
Similarly u1 = u2
u2 = u3 and so on
u = constant for n=∞
Links of Previous Main Topic:-
- Open system and control volume
- Conversion of work into heat
- Introduction to carnot cycle
- Clausius inequality entropy and irreversibility introduction
- Ideal gas or perfect gas
- Ideal gas or perfect gas
- Specific heats internal energy and enthalpy of an ideal gas
- Entropy change of an ideal gas
- Reversible adiabatic process
- P v and t s diagrams for pv c
Links of Next Mechanical Engineering Topics:-
