There are some underlying assumptions extracted from the transportation model:

Availability of the commodity: if the supply of the numerous sources is equal then it is called a balanced problem, and if it is more than the total demand of the destinations then it has to be balanced.

i.e.    _i=1ʃ^ma_{i = j=1}ʃⁿ b_i

1. Transportation of commodity/terms: the model assumes that the commodities are being transported from the source to the destination very conveniently.
2. The certainty of per unit transportation cost: obviously there is some transportation cost between the sources and destination.
3. Independent per cost unit: per cost unit does not depend on the quantity being transported from source to destination.
4. A number of units being transportedare proportional to the transportation cost of any route.
5. The objective is to minimise the transportation cost for transporting commodities between two places.

Example 5.1

A car manufacturing company has factories at places A, B and C. the cars have to reach destinations at cities X and Y. the capacity of the factories during the next quarter is 1000, 1500 and 1200 cars. The quarterly demand of the two cities X and Y 2300 and 1400 cars if transported by train then the per car transportation cost per km is Rs. 8.

Here is the chart showing the distance between the factory and destination.

X                                                           Y

1000                                                 2690

1250                                                  1350

1275                                                   850

Now calculate how many cars should be transported from which factory to which destination to minimise the cost?

Solution:

Step I:The market distance and the cost of transportation per km are given to us, and that must be converted into costs.

                                                  X                                                     Y

A                                             2000                                              5380

B                                             2500                                               2700

C                                              2550                                               1770

Let us assume X_ijas the number of cars that are transported from factories to the destination cities. Since the total supply (1000+1500+1200=3700) happens to equal the total demand (2300+1400=3700). Thus the transportation model is balanced.

                                                             X                                         Y                                Supply

                                    A                      X₁₁                                                         X₁₂                                           1000

Source                        B                      X₂₁                                                         X₂₂                                            1500

                                    C                       X₃₁                                                        X₃₂                                             1200

                             Demand               2300                                  1400                            3700

Step II: minimize the transportation cost between the source and destination

I.e. Z = 2000 X₁₁ + 5380 X₁₂ + 2500 X₂₁ + 2700 X₂₂ + 2550 X₃₁ + 1700 X₃₂

In general, if C is the unit cost of transportation from ith source to jth destination, the objective is

Minimize_i=1ʃ ^m_j=1ʃⁿ C_ij X_ij

Step III. Constraints

(a) Availability or supply of cars

X₁₁ + X₁₂ = 1000 (Source A)

X₂₁ + X₂₂ = 1500 (Source B)

X₃₁ + X₃₂ = 1200 (Source C)

As we have three factories hence there are three constraints.

(b) Demand of cars at the destination

X11 + X21 + X31 = 2300 (Destination center X)

X12 + X22 + X32 = 1400 (Destination center Y)

In this problem there are (m × n) variables i.e. (3 × 2= 6) variables and (m + n) constraints which is (3+2=6).

So from all the above steps it is evident enough that the objective function and constraint equations are linear as a result it can be solved by LPP or simplex method. But 6 variables or even more (in real life) will take a lot of time for the calculations. Therefore a computer aid is required. A point to remember is the simplex method best applicable for maximising the problems, but our motive is minimising the objective function.

SOLUTION OF THE TRANSPORTATION MODEL

Step I: Create a transportation model

Distribution centers

                                                              X                                         Y                supply

                              A                        Rs.2000

Factories                                       X₁₁= 1000                           Rs= 5380                        1000

                              B                         Rs.2500                             Rs. 2700

                                                         X₂₁=1300                            X₂₂=1400                    +1500

                              C                        Rs. 2550                               Rs. 1700                         +1200

                        Demand                    2300                                     +1400                           =3700

The above problem is thus balanced and when it is not so then a dummy source is createdto balance the demand and supply.

Step II: finding a basic feasible solution

There are many methods to determine the possible basicmethod. Out of the many methods, ‘north-west corner rule’ Dantzig is one.

Links of Previous Main Topic:-

• Concept of capital expenditure
• Learning objectives and chapter outline
• Limitations of operations research
• Linear programming learning objectives and outline of chapter
• Introduction learning objectives
• Duality in linear programming
• Learning objectives

Links of Next Finance Topics:-

• North west corner rule
• Row minima method
• Column minima method
• Least cost method
• Vogels approximation method vam
• Performing optimality test
• The stepping stone method
• The modified distribution modi method or uv method
• Learning objectives and chapter outline in assignment model
• Minimization problems
• Learning objectives the transportation problems
• Special case of traveling sales man problem
• Replacement theory learning objectives and chapter outline
• Learning objectives and chapter outline for waiting line queuing theory

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