Take a Help in Simplification Assignment Answers
Simplifying the Simplification Homework Answers for You
Simplification Homework Answers are available at myhomeworkhelp.com to help you understand the process. It is generally used to simplify an equation or find the value of any variable. It is used all across Mathematics and its branches as it is the basic lesson we learn to solve an equation.
With the help of Simplification Assignment Answers we are able to solve complex equations and find out the missing figures. It is used widely to calculate the area, volume and measurement in Mensuration, the angles in Geometry, the value of variables in Linear and Algebraic Equations. Thus, it is present in all topics of Mathematics and its related branches.
Basic of Simplification Homework Answers
The basic lesson in Simplification is the BODMAS rule. As kids that were the first thing we learnt to solve simple equations. We still use it as graduates and students of higher studies. We have explained the BODMAS rule below:
B- B stands for bracket and anything in a bracket in an equation is solved first. The level of precedence of brackets in ascending order are (), {} and []. If all the brackets are present in an equation we solve the part with the normal brackets i.e. (). Then we solve the one with the curly brackets i.e. {}. Ultimately, we solve the part with the block brackets which are [].
O – O stands for “of” in an equation. After the brackets we solve the function in the equation. For example 1/3 of 9 means 1/3 × 9 = 3.
D – D stands for division. And after B and O we solve the division in an equation.
M – M stands for multiplication. It is simple multiplication of two numbers or parts of an equation.
A – A stands for addition of two numbers in the equation.
S – The last part of the BODMAS rule is S which stands for Subtraction.
Example of using BODMAS rule in an equation
To get a better understanding of the BODMAS rule and its application we are going to take an example. Take the following equation as the example
[2 x {3 + 6 (10 ÷ 5)}]
= [2 x {3 + 6 (2)}]
= [2 x {3 + 12}]
= [2 x {15}]
= [2 x 15]
= 30
So we can see that in the above example we first used the brackets of BODMAS. We solved the equations while keeping the precedence of the various brackets and solved the equation within them.
Let’s take another example to further explain the complexities in an equation:
10 × [90 – {2 x (3 of 9 – 10)}]
= 10 x [90 – {2 x (18 – 10)}]
= 10 x [90 – {2 x 8}]
= 10 x [90 – 16]
= 10 x 74
= 740
Here we solved the brackets first but in the first bracket we saw that there were 2 parts. So keeping in mind the BODMAS rule we solved the part first then the other part.
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