Power Stages in an Induction Motor

There are generally 3 power stages of an induction motor

  1. Stator iron loss which generally consists of hysteresis and eddy losses is dependent on the flux density and supply frequency in the core of iron which is also stated as practically constant.
  2. Since the frequency of rotor current is always smaller under the normal running conditions, it results into negligible rotor iron loss.
  3. the total rotor copper loss = 3I22R2

Considering I2 and R2 as respective current and resistance of the rotor

17.1. Rotor output


Stator input = stator output + losses

Rotor input = stator output

(Stator output will entirely inductively transfer to the rotor circuit)

Rotor gross output = rotor input – rotor copper losses.

The rotor output then gives rise to the gross Torque Tg by converting into the mechanical energy. Please note that some of the gross torque is also lost because of the windage and friction loss in the rotor. The rest of the gross torque appears as Tsh as the useful/shaft torque.

If Tg is in N-m and N is the actual speed of the rotor in r.p.m.

17.2. Synchronous watt

A synchronous wall is termed as the value of torque as the synchronous speed of motor. This new unit of torque develops a power of one watt. Let’s consider an example; if the motor is developing a torque of 750 synchronous watts, it reflects that the input of the rotor is 750 watts and the torque which is examined such that the power will be developed by 500 watts. It reflects that the rotor is developing the same torque which synchronized run.

It shows that the synchronous wattage is equal to the power transferred to the rotor across air-gap of an induction motor.

17.3. Factors determining torque

Let’s assume that a 3-phase induction motor is operated with slip‘s’ on a certain load,  then

Induced electromotive force (e.m.f) per phase in rotor = sF2 volts

(Where E2 = standstill rotor induced e.m.f.)

Rotor impedance per phase, Z2= R2 + jsX2

(Where R2 and X2 are rotor resistance and standstill reactance per phase)


Example 1. The power input to a 3-phase induction motor is 60 k W. The stator-losses total 1.5 kW. If the motor is running with a slip of 5 per cent, find the total mechanical power developed,

Solution. Stator power input = 60 kW

Stator losses = 1.5 kW

Slip                                  , = 4% (= 0.04)

Mechanical power developed:

Rotor input = stator output = stator input – stator losses

= 60 – 1.5 = 58.5 kW

Now mechanical power developed

= (1 – s) rotor input

= (1- 0.04) × 58.5

= 46.16kW. (Ans.)

Example 2.A 60 H.P., 6-pole, 60 Hz, slip-ring induction motor with a rotor current of 50 A is running on full Load at 960 r.p.m. Allowing 400 W for copper loss in the short-circuiting gear and 1500 W for mechanical losses, find the resistance R2 per phase of the 3-phase rotor winding.

(GATE, 1998)

Solution. Pout = 60 H.P. = 60 × 735.5 = 44130 W ;

p = 6 ;

f = 60 Hz ;

N = 980 r.p.m. ;

I2 = 50 A ;

copper loss in the short-circuiting gear = 400 W ; mechanical loss = 1500 W.

Resistance, R2:

Rotor output = motor output + short-circuiting gear loss + mechanical losses

= 44130 + 400 + 1500 = 46030 W


We’re rated Excellent

4.7 out of 5 based on 39 reviews

Order Homework Help
Click or drag files to this area to upload. You can upload up to 5 files.
We do not share numbers with 3rd party.

Join over 200,000+ happy students served our tutors

Take a look at independent reviews to see what users have to say about our homework help service.


overall rating
on LiveChat


of users
recommend service

How It Works

1. Get Price Estimate.
1. Get Price Estimate.


Send us your homework. Mention deadline & upload relevant files.

2. Pay Securely.
2. Pay Securely.


We accept all major credit cards. Partial payments also accepted.

3. Get Solutions.
3. Get Solutions.


Receive error-free, step-by-step solutions in your email.


Why use Myhomeworkhelp?

We provide you with the homework help from top experienced experts. Your satisfaction is a priority to us. Get better grades or money-back. It’s that risk-free! Furthermore, everything about you is kept confidential.

How quickly can you help me with my homework?

We take pride in our 24×7 homework help services. Which means, student can approach us anytime, to get help even on short notices. As short as few hours! And yes, we provide complementary plagiarism-free report.

How much will it cost?

We do not have a monthly fees or minimum payments. Each homework task is quoted a unique price. It is based on tutor’s estimate of the time it will take them to complete your task. There are no obligations, and you are free to discuss the price quote with the tutor.
We do accept partial payment (subject to our policy) to start working on your assignment help. You can pay the remaining amount when your task gets completed. No pressure of up-front payment. No hidden costs.

Who are your tutors?

All our experts are highly qualified professionals – holding at least Master’s degree of their respective fields of expertise. We are very selective and choose only the best qualified tutors for each academic subject. All tutor applicants must provide academic transcripts for each degree they hold, and are tested and screened carefully by our staff.

I have privacy concerns. Can I trust you?

Myhomeworkhelp has completed over 250,000 homework help tasks over the last 12 years. But do not take our word for it! See our here and on Trustpilot. Furthermore, everything about you is kept confidential. Your credit card information is not stored anywhere, and use of PayPal relies on their secure payment networks. Your identity, payment and homework help are in safe hands.

Check our video

Our Reviews